Back in August 2007 one of our columns was based on a
quest to find two fractions, made up from the ten integers 1, 2, 3,
4, 5, 6, 7, 8, 9 and 0, which sum to unity. The answer
was:
This week's problem is similar but perhaps more difficult:
Can you place the shorter sequence of nine integers 1, 2, 3, 4,
5, 6, 7, 8 and 9 so as to equal unity? In other words, identify the
six digits hidden behind A, B, C, D, E and F. The lefthand fraction
has been identified to give you a clue.
Find the solution online >>
