Jim Moyles, a new contributor from Crowthorne in Berkshire, has
been analysing the Puzzler of 5 August. This was based on
(AB+CD)2 = A,BCD, where both sides of the equation had
the same four different digits in the same order. The solution was
A,BCD = 3025
Mr Moyles extended the theme, and soon found
(494+209)2 = 494,209 and (5288+1984)2 =
52,881,984. These are interesting, but the basic sum does not have
all its digits different. Further work, however, produced the
equation:
(A,BCD+E,FGH)2 = AB,CDE,FGH
Identifying the eight different digits here is this week's
problem.
Find the solution online>>
Please post all Puzzler enquiries and contributions to: Jim
Howson, 5 Hilltop Gardens, Dartford, Kent DA1 5JF
